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"<div class='mcq-vertical cheveron-helper'><div class='mcq-title'><p><div class=\"mathText\">The\\;number\\;obtained\\;on\\;rationalizing\\;the\\;denominator\\;of\\;\\;\\frac1{\\sqrt{7-2}}\\;\\;is</div></p></div><i class='chevron down icon'></i><div class='mcq-options'><div data-simple-choice-interaction data-response-variable='responseValue' value=0 class='mcq-option'><p><div class=\"mathText\">\\sqrt{\\frac{7-2}3}</div></p></div><div data-simple-choice-interaction data-response-variable='responseValue' value=1 class='mcq-option'><p><div class=\"mathText\">\\sqrt{\\frac{7+2}3}</div></p></div><div data-simple-choice-interaction data-response-variable='responseValue' value=2 class='mcq-option'><p><div class=\"mathText\">\\sqrt{\\frac{7+2}5}</div></p></div><div data-simple-choice-interaction data-response-variable='responseValue' value=3 class='mcq-option'><p><div class=\"mathText\">\\sqrt{\\frac{7+2}{45}}</div></p></div></div></div>",
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<p>Find two irrational numbers between 1.12 and 1.13 </p>",
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<p>(a) 1.121221222</p><p>(b) 1.12212221222</p>"
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The method of plotting square root of natural and decimal numbers on the number line."
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<p><math xmlns=\"http://www.w3.org/1998/Math/MathML\"><mi>R</mi><mi>a</mi><mi>t</mi><mi>i</mi><mi>o</mi><mi>n</mi><mi>a</mi><mi>l</mi><mi>i</mi><mi>s</mi><mi>e</mi><mo> </mo><mi>t</mi><mi>h</mi><mi>e</mi><mo> </mo><mi>d</mi><mi>e</mi><mi>n</mi><mi>o</mi><mi>m</mi><mi>i</mi><mi>n</mi><mi>a</mi><mi>t</mi><mi>o</mi><mi>r</mi><mo> </mo><mo>:</mo><mo> </mo><mfrac><mn>1</mn><mrow><msqrt><mn>7</mn></msqrt><mo>+</mo><msqrt><mn>6</mn></msqrt><mo>-</mo><msqrt><mn>13</mn></msqrt></mrow></mfrac></math></p>",
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"<p><div class=\"mathText\">\\begin{array}{l}=\\frac{1\\times\\left\\{\\left(\\sqrt7+\\sqrt6\\right)+(\\sqrt{13})\\right\\}}{\\left\\{\\left(\\sqrt7+\\sqrt{16}\\right)-\\left(\\sqrt{13}\\right)\\right\\}\\{(\\sqrt7+\\sqrt6)+(\\sqrt{13})\\}}\\\\=\\frac{\\sqrt7+\\sqrt6+\\sqrt{13}}{(\\sqrt7+\\sqrt6)^2-(\\sqrt{13})^2}\\\\=\\frac{\\sqrt7+\\sqrt6\\sqrt{13}}{7+6+2\\sqrt{2-13}}\\\\=\\frac{\\left(\\sqrt7+\\sqrt6+\\sqrt{13}\\right)\\times\\sqrt{42}}{(2\\sqrt{42})\\times(\\sqrt{42})}\\\\=\\frac{\\left(\\sqrt{7\\times42}+\\sqrt{6\\times42}+\\sqrt{13\\times42}\\right)}{84}\\\\=\\frac{7\\sqrt6+6\\sqrt7+546}{84}\\end{array}</div></p>"
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